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48y^2-64y+21=0
a = 48; b = -64; c = +21;
Δ = b2-4ac
Δ = -642-4·48·21
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8}{2*48}=\frac{56}{96} =7/12 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8}{2*48}=\frac{72}{96} =3/4 $
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